When the second resistor is removed from the series circuit, what happens to the voltage drop and current through the first resistor?

In a series circuit, the total voltage across the circuit is distributed among the resistors based on their resistances. When the second resistor is removed from the series circuit, the total resistance of the circuit decreases. According to Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R) (I = V/R), a decrease in the total resistance leads to an increase in current flowing through the circuit, assuming the voltage source remains the same.

With respect to the voltage drop across the first resistor, since the total current in the circuit has increased due to the lower resistance, the voltage drop across the first resistor is given by the formula V = I * R. As the current increases and the resistance of the first resistor remains constant, the voltage drop across that resistor will also increase.

Therefore, when the second resistor is removed, both the current through the first resistor increases due to the decreased total resistance, and the voltage drop across the first resistor increases as well, reflecting the increase in current flowing through it.